.. I mistakenly thought that adding each of the upward forces and downward forces of the two masses plus the fulcrum would give me the proper response. Therefore the upward force (ordinary) exerted by the fulcrum will have to stability the downward forces exerted by the two masses and also the fulcrum in order for the seesaw to generally be in equilibrium. Remember to appropriate me, if I'm Mistaken. Any assistance could well be excellent. Thanks.
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If you want to ascertain the not known weight or force in a seesaw issue, you could setup a torque equation and remedy to the not known variable.
haruspex claimed: Of course, other than that, strictly speaking, in case you are looking at the seesaw as being the free of charge human body then you ought to create N1, N2 for typical forces in the masses. In separate equations for the people masses as cost-free bodies you then acquire N1=m1g etc.
bijou1 stated: I mistakenly considered that introducing all the upward forces and downward forces of the two masses plus the fulcrum would give me the correct reply. Unsure what you imply by that, however, you had this equation
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The traditional power is simply existing When contemplating each mass as being a different cost-free system. When you are trying to discover the response force for the fulcrum, the sum in the forces features the weight in the beam and the burden of any masses resting on it. So when trying to find the reactionary pressure (typical) exerted because of the fulcrum, I need to begin to see the fulcrum and the 2 masses resting on it being a absolutely free body (totally free overall body of fulcrum) in its entirety.
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